大智慧金銀三角買(mǎi)入法指標(biāo)公式
大智慧指標(biāo)公式源碼概況：
- 指標(biāo)類(lèi)別： 大智慧指標(biāo)公式
- 授權(quán)方式： 免費(fèi)版
- 指標(biāo)評(píng)級(jí)： ★★★★★
- 指標(biāo)分類(lèi)： 均線
- 畫(huà)線方法： 主圖
- 日期：2018-09-11 來(lái)源：互聯(lián)網(wǎng)
大智慧指標(biāo)公式源碼介紹：
大智慧金銀三角買(mǎi)入法指標(biāo)公式：三角托的特征：在5天、10天、30天（或20天）均線組合中，5天均線由下向上先 后金叉10天、30天均線，10天均線再金叉30天均線，三條均線圍成一個(gè)三角形狀 ，取名為三角托（可推廣到任意三條均線）。三角托出現(xiàn)，三條均線開(kāi)始呈多頭 排列，是做多的信號(hào)。
三角托有銀三角托與金三角托之分，區(qū)別在于：出現(xiàn)的時(shí) 間先后不同。股價(jià)經(jīng)一輪下跌后出現(xiàn)的第一個(gè)三角托便是銀三角托。銀三角托出 現(xiàn)后股價(jià)經(jīng)過(guò)一輪上升再回檔整理，此時(shí)出現(xiàn)的三角托便是金三角托，也叫雙三 角托。金三角托的位置稍高于銀三角托，也有少數(shù)會(huì)稍低于銀三角托。金三角托 是對(duì)銀三角托做多信號(hào)的確認(rèn)，發(fā)出的買(mǎi)入信號(hào)比銀三角托更為可靠。
買(mǎi)入 時(shí)機(jī)的選擇：1、激進(jìn)型的買(mǎi)入時(shí)機(jī)：在銀三角托剛形成，股價(jià)已在30天均線上方 運(yùn)行時(shí)介入。
MA5:MA(C,5);
MA10 :MA(close,10);
MA30 : MA(close,30);
GJTJ1:=100*(C-LLV(L,5))/(HHV(C,5)-LLV(L,5));
GJTJ2:=100*(C-LLV(L,10))/(HHV(C,10)-LLV(L,10));
GJTJ3:=100*(C-LLV(L,20))/(HHV(C,20)-LLV(L,20));
GJTJ4:=100*(C-LLV(L,30))/(HHV(C,30)-LLV(L,30));
baijin1:=BARSLAST(CROSS(30,GJTJ1))<2 AND BARSLAST(CROSS(GJTJ1,50))<2;
baijin2:=BARSLAST(CROSS(GJTJ4,GJTJ1))<2 AND GJTJ1>GJTJ4;
baijin3:=GJTJ1>60 AND GJTJ4>70;
drawtext(baijin1 AND baijin2 AND baijin3,l-0.02,'白金'),colorffffff;
huangjin1:=BARSLAST(CROSS(50,GJTJ1))<3 AND BARSLAST(CROSS(GJTJ1,50))<3;
huangjin2:=BARSLAST(CROSS(GJTJ4,GJTJ1))<2 AND GJTJ1>GJTJ4;
DRAWTEXT(huangjin1 AND huangjin2,l-0.03,'黃金'),colorffffff;
XG:=BARSLAST(CROSS(GJTJ4,GJTJ1))<5 AND GJTJ1>GJTJ4;
drawtext(COUNT(XG,3)=1 AND XG and c>ma(c,20),l-0.02,'啟動(dòng)金三角'),colorred;
zhencang1:=BARSLAST(CROSS(GJTJ4,GJTJ1))>3 AND BARSLAST(CROSS(GJTJ1,GJTJ4))<3;
zhencang2:=BARSLAST(CROSS(GJTJ4,GJTJ2));
zhencang3:=GJTJ3 zhencang4:=BARSLAST(CROSS(GJTJ4,GJTJ3))>3 AND BARSLAST(CROSS(GJTJ1,GJTJ4))<3;
zhencang5:=GJTJ2 zcB1:=zhencang1>0 AND REF(zhencang1,1)=0 AND REF(zhencang1,2)>0;
drawtext(zhencang1 AND zhencang2 AND zhencang3 AND zhencang4 AND zhencang5,l-0.05,'震倉(cāng)啟點(diǎn)');
Aa:=BARSLAST(CROSS(97,GJTJ1))<=1 AND BARSLAST(CROSS(GJTJ1,85))<=1;
Bb:=BARSLAST(CROSS(97,GJTJ2))<=1 AND BARSLAST(CROSS(GJTJ2,85))<=1;
Aa1:=Aa AND Bb;
AAa:=BARSLAST(CROSS(97,GJTJ1))<=2 AND BARSLAST(CROSS(GJTJ1,85))<=1;
BAa:=BARSLAST(CROSS(97,GJTJ2))<=2 AND BARSLAST(CROSS(GJTJ2,85))<=1;
Aa2:=AA AND Bb ;
AAAa:=BARSLAST(CROSS(97,GJTJ1))<=3 AND BARSLAST(CROSS(GJTJ1,85))<=1;
BAAa:=BARSLAST(CROSS(97,GJTJ2))<=3 AND BARSLAST(CROSS(GJTJ2,85))<=1;
Aa3:=AAAa AND BAAa ;
Bb1:=REF(Aa1,1);
Bb2:=REF(Aa2,1);
Bb3:=REF(Aa3,1);
Dd1:=GJTJ1=100 AND GJTJ2=100 AND Aa1 ;
Dd2:=GJTJ1=100 AND GJTJ2=100 AND Aa2 ;
Dd3:=GJTJ1=100 AND GJTJ2=100 AND Aa3 ;
drawtext(Dd1 OR Dd2 OR Dd3,l-0.02,'短線追漲'),colorffffff;
Aw:=BARSLAST(CROSS(95,GJTJ1))<=2;
Bw:=BARSLAST(CROSS(95,GJTJ2))<=2;
Ew:= GJTJ4 Fw:=GJTJ2>50 AND GJTJ3>50;
Gw:=GJTJ1=100 AND GJTJ2=100;
TXw:=COUNT(Gw,2)=1;
drawtext(Aw AND Bw AND Ew AND Fw AND TXw,l-0.03,'起漲首日'),colorffffff;
Aq:=GJTJ3=100;
Bq:=GJTJ4<90;
drawtext(COUNT(Aq,2) = 2 AND Bq,l-0.02,'波啟前兆'),colorffffff;
MA10 :MA(close,10);
MA30 : MA(close,30);
GJTJ1:=100*(C-LLV(L,5))/(HHV(C,5)-LLV(L,5));
GJTJ2:=100*(C-LLV(L,10))/(HHV(C,10)-LLV(L,10));
GJTJ3:=100*(C-LLV(L,20))/(HHV(C,20)-LLV(L,20));
GJTJ4:=100*(C-LLV(L,30))/(HHV(C,30)-LLV(L,30));
baijin1:=BARSLAST(CROSS(30,GJTJ1))<2 AND BARSLAST(CROSS(GJTJ1,50))<2;
baijin2:=BARSLAST(CROSS(GJTJ4,GJTJ1))<2 AND GJTJ1>GJTJ4;
baijin3:=GJTJ1>60 AND GJTJ4>70;
drawtext(baijin1 AND baijin2 AND baijin3,l-0.02,'白金'),colorffffff;
huangjin1:=BARSLAST(CROSS(50,GJTJ1))<3 AND BARSLAST(CROSS(GJTJ1,50))<3;
huangjin2:=BARSLAST(CROSS(GJTJ4,GJTJ1))<2 AND GJTJ1>GJTJ4;
DRAWTEXT(huangjin1 AND huangjin2,l-0.03,'黃金'),colorffffff;
XG:=BARSLAST(CROSS(GJTJ4,GJTJ1))<5 AND GJTJ1>GJTJ4;
drawtext(COUNT(XG,3)=1 AND XG and c>ma(c,20),l-0.02,'啟動(dòng)金三角'),colorred;
zhencang1:=BARSLAST(CROSS(GJTJ4,GJTJ1))>3 AND BARSLAST(CROSS(GJTJ1,GJTJ4))<3;
zhencang2:=BARSLAST(CROSS(GJTJ4,GJTJ2));
zhencang3:=GJTJ3
zhencang5:=GJTJ2
drawtext(zhencang1 AND zhencang2 AND zhencang3 AND zhencang4 AND zhencang5,l-0.05,'震倉(cāng)啟點(diǎn)');
Aa:=BARSLAST(CROSS(97,GJTJ1))<=1 AND BARSLAST(CROSS(GJTJ1,85))<=1;
Bb:=BARSLAST(CROSS(97,GJTJ2))<=1 AND BARSLAST(CROSS(GJTJ2,85))<=1;
Aa1:=Aa AND Bb;
AAa:=BARSLAST(CROSS(97,GJTJ1))<=2 AND BARSLAST(CROSS(GJTJ1,85))<=1;
BAa:=BARSLAST(CROSS(97,GJTJ2))<=2 AND BARSLAST(CROSS(GJTJ2,85))<=1;
Aa2:=AA AND Bb ;
AAAa:=BARSLAST(CROSS(97,GJTJ1))<=3 AND BARSLAST(CROSS(GJTJ1,85))<=1;
BAAa:=BARSLAST(CROSS(97,GJTJ2))<=3 AND BARSLAST(CROSS(GJTJ2,85))<=1;
Aa3:=AAAa AND BAAa ;
Bb1:=REF(Aa1,1);
Bb2:=REF(Aa2,1);
Bb3:=REF(Aa3,1);
Dd1:=GJTJ1=100 AND GJTJ2=100 AND Aa1 ;
Dd2:=GJTJ1=100 AND GJTJ2=100 AND Aa2 ;
Dd3:=GJTJ1=100 AND GJTJ2=100 AND Aa3 ;
drawtext(Dd1 OR Dd2 OR Dd3,l-0.02,'短線追漲'),colorffffff;
Aw:=BARSLAST(CROSS(95,GJTJ1))<=2;
Bw:=BARSLAST(CROSS(95,GJTJ2))<=2;
Ew:= GJTJ4
Gw:=GJTJ1=100 AND GJTJ2=100;
TXw:=COUNT(Gw,2)=1;
drawtext(Aw AND Bw AND Ew AND Fw AND TXw,l-0.03,'起漲首日'),colorffffff;
Aq:=GJTJ3=100;
Bq:=GJTJ4<90;
drawtext(COUNT(Aq,2) = 2 AND Bq,l-0.02,'波啟前兆'),colorffffff;
大智慧金銀三角買(mǎi)入法指標(biāo)公式實(shí)例圖解：
大智慧金銀三角買(mǎi)入法指標(biāo)公式
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